A spider climbed 62\(\frac{1}{2}\)% of the height of a pole in one hour and in the next hour it covered 12\(\frac{1}{2}\)% of the remaining height. If pole's height is 192m, then the distance climbed in second hour is:

9 m

62\(\frac{1}{2}\)% = \(\frac{5}{8}\) and  12\(\frac{1}{2}\)% = \(\frac{1}{8}\)

Height covered in 1st hour:

⇒ 192 × \(\frac{5}{8}\) ⇒ 120 m

Remaining height⇒ 192-120 = 72 m

Height covered in 2nd hr:

⇒ 72 × \(\frac{1}{8}\) = 9m