A spider climbed 62\(\frac{1}{2}\)% of the height of a pole in one hour and in the next hour it covered 12\(\frac{1}{2}\)% of the remaining height. If pole's height is 192m, then the distance climbed in second hour is:
Answer & explanation
Correct answer: option 4
62\(\frac{1}{2}\)% = \(\frac{5}{8}\) and 12\(\frac{1}{2}\)% = \(\frac{1}{8}\)
Height covered in 1st hour:
⇒ 192 × \(\frac{5}{8}\) ⇒ 120 m
Remaining height⇒ 192-120 = 72 m
Height covered in 2nd hr:
⇒ 72 × \(\frac{1}{8}\) = 9m