A dishonest grocer professes to sell pure milk at cost price but he mixes it with water and thereby gains 25%. Find the percentage of water in the mixture assuming that water is freely available.
Answer & explanation
Correct answer: option 2
25% profit ⇒ \(\frac{1(water)}{4(milk) }\)
Milk : Water : total mixture
4 : 1 : 5
% of water in mixture ⇒ \(\frac{1}{5}\) × 100 = 20%