If tanθ + cot θ = 9 , find the value of tan2θ + cot2θ .

88 83 81 79

79

Formula I → [ tanθ = \(\frac{1}{cotθ}\)] Formula II → [If x + \(\frac{1}{x}\) = n and x2 + \(\frac{1}{x^2}\) = n2 - 2] tanθ + \(\frac{1}{tanθ}\) = 9 ⇒ tan2θ + \(\frac{1}{tan^2θ}\) = (9)2 - 2 ⇒ tan2θ + cot2θ = 81 - 2 = 79