A slit of width e is illuminated by light of wavelength λ. What should be the value of e to obtain the first maximum at an angle of diffraction of $\frac{\pi}{3}$? |
$\frac{2}{\sqrt{3}}λ$ $\frac{λ}{\sqrt{3}}$ $\sqrt{3}λ$ $\frac{\sqrt{3}}{2}λ$ |
$\sqrt{3}λ$ |
$\text{For single slit diffraction, maxima condition (approx): } e\sin\theta = \frac{(2m+1)\lambda}{2}$ $\text{First maximum: } m=1$ $e\sin\theta = \frac{3\lambda}{2}$ $\theta=\frac{\pi}{3} \Rightarrow \sin\theta=\frac{\sqrt{3}}{2}$ $e \cdot \frac{\sqrt{3}}{2} = \frac{3\lambda}{2}$ $e = \frac{3\lambda}{\sqrt{3}} = \sqrt{3}\lambda$ $e = \sqrt{3}\lambda$ |