Practicing Success
A substance reacts according to first-order kinetics. The rate constant for the reaction is 1 x 10–2 sec-1. Its initial concentration is 1M. Its initial rate is: |
2 × 102 Ms–1 1 × 102 Ms–1 1 × 10–2 Ms–1 2 × 10–2 Ms–1 |
1 × 10–2 Ms–1 |
The correct answer is option 3. 1 × 10–2 Ms–1. To determine the initial rate of a reaction, we can use the first-order rate equation: \(\text{Rate} = k[A] \) where \(\text{Rate}\) is the rate of the reaction, \(k\) is the rate constant, and \([A]\) is the concentration of the reactant. Given that the rate constant (\(k\)) is \(1 \times 10^{-2} \, \text{sec}^{-1}\) and the initial concentration (\([A]_0\)) is \(1 \, \text{M}\), we can substitute these values into the rate equation to find the initial rate (\(\text{Rate}_0\)): \(\text{Rate}_0 = k \times [A]_0 \) \(\text{Rate}_0 = (1 \times 10^{-2} \, \text{sec}^{-1}) \times (1 \, \text{M}) \) \(\text{Rate}_0 = 1 \times 10^{-2} \, \text{M/sec} \) Therefore, the correct answer is \((3) \, 1 \times 10^{-2} \, \text{Ms}^{-1}\). |