Value of $[\vec{a} \times \vec{b}, \vec{a} \times \vec{c}, \vec{d}]$ is always equal to:
Answer & explanation
Correct answer: option 1
${[\vec{a} \times \vec{b}, \vec{a} \times \vec{c}, \vec{d}]}$
$=(\vec{a} \times \vec{b}) .((\vec{a} \times \vec{c}) \times \vec{d})$
$=(\vec{a} \times \vec{b}) .((\vec{a} . \vec{d}) \vec{c}-(\vec{c} . \vec{d}) \vec{a})$
$=(\vec{a} . \vec{d})[\vec{a} \vec{b} \vec{c}]$
Hence (1) is correct answer.