Consider that $p_0, q_0$ represents price and quantity of base year and $p_1, q_1$ represents price and quantity for the current year. Given that $\sum p_0 q_0=584, \sum p_0 q_1=484$. $\sum p_1 q_0=623$ and $\sum p_1 q_1=517$. Which of the following gives Fisher's price Index Number $\left(P_{01}\right)$? |
$P_{01}=\sqrt{\frac{623 \times 517}{584 \times 484}} \times 100$ $P_{01}=\sqrt{\frac{6.23 \times 5.17}{5.84 \times 4.84}} \times \log _e 2$ $P_{01}=\frac{584 \times 484}{623 \times 517}$ $P_{01}=\sqrt{\frac{584 \times 484}{623 \times 517}} \times 100$ |
$P_{01}=\sqrt{\frac{623 \times 517}{584 \times 484}} \times 100$ |
The correct answer is Option (1) → $P_{01}=\sqrt{\frac{623 \times 517}{584 \times 484}} \times 100$ $\text{Laspeyres index} = \frac{\sum p_1 q_0}{\sum p_0 q_0} \times 100 = \frac{623}{584}\times100$ $\text{Paasche index} = \frac{\sum p_1 q_1}{\sum p_0 q_1} \times 100 = \frac{517}{484}\times100$ $\text{Fisher index} = \sqrt{\left(\frac{623}{584}\times100\right)\left(\frac{517}{484}\times100\right)}$ $= 100\sqrt{\frac{623\times517}{584\times484}}$ $P_{01} = 100\sqrt{\frac{623\times517}{584\times484}}$ |