64 identical cubes are cut from a big cube and all the smaller cubes are arranged in a row to form a long cuboid. What is the percentage increase in the total surface area of the cuboid over the total surface area of the cube?

168.75%

The volume 64 smaller cubes = The volume of 1 bigger cube

                           64(edge₁)³ = (edge₂)³

                               4(edge₁) = (edge₂)

Let the edge of smaller cubes = 1 unit,

The edge of bigger cube = 4 units 

The dimensions of the cuboid such formed = 64 x 1 x 1

Surface area of cuboid =  2(lb + bh +  lh) = 2(64 + 1 + 64) = 258

Surface area of 1 bigger cube =  6 (4)² = 96

Surface area increased = 258 - 96 = 162

Percentage increase = \(\frac{162}{96}\) x 100 = 168.75%