In a swimming pool measuring 80 m × 60 m, 120 men take a dip. If the average displacement of water by a man is 6 m3, then the rise in water level is –
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 0.15 m
The water pushed aside by the men spreads over the whole floor of the pool and raises the level. So the volume displaced equals the base area of the pool times the rise in level.
Volume displaced \(=120\times6=720\) m3
Base area of the pool \(=80\times60=4800\) m2
Rise in level \(\displaystyle =\frac{720}{4800}=0.15\) m