Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Determinants

Question:

Match List - I with List - II. If $A=\left|\begin{array}{rrr}3 & -2 & 3 \\ 2 & 1 & -1 \\ 4 & -3 & 2\end{array}\right|$

List - I

  List - II  

 (A) $M_{23}$

 (I) -17 

 (B) $A_{32}+a_{13}$

 (II) -1 

 (C) $A$

 (III) 0

 (D) $a_{13} A_{12}+a_{23} A_{22}+a_{33} A_{32}$

 (IV) 12 

Choose the correct answer from the options given below:

Options:

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

Correct Answer:

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Explanation:

The correct answer is Option (2) - (A)-(II), (B)-(IV), (C)-(I), (D)-(III)

(A) $M_{23}=\begin{vmatrix}3&-2\\4&-3\end{vmatrix}=-1$ (II)

(B) $A_{32}+a_{13}=(-1)^5\begin{vmatrix}3&3\\2&-1\end{vmatrix}+3=12$ (IV)

(C) $A=3\begin{vmatrix}1&-1\\-3&2\end{vmatrix}+2\begin{vmatrix}2&-1\\4&2\end{vmatrix}+3\begin{vmatrix}2&1\\4&-3\end{vmatrix}=-17$ (I)

(D) $a_{13} A_{12}+a_{23} A_{22}+a_{33} A_{32}=0$ (III)