Practicing Success
Match List - I with List - II. If $A=\left|\begin{array}{rrr}3 & -2 & 3 \\ 2 & 1 & -1 \\ 4 & -3 & 2\end{array}\right|$
Choose the correct answer from the options given below: |
(A)-(II), (B)-(I), (C)-(IV), (D)-(III) (A)-(II), (B)-(IV), (C)-(I), (D)-(III) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) |
(A)-(II), (B)-(IV), (C)-(I), (D)-(III) |
The correct answer is Option (2) - (A)-(II), (B)-(IV), (C)-(I), (D)-(III) (A) $M_{23}=\begin{vmatrix}3&-2\\4&-3\end{vmatrix}=-1$ (II) (B) $A_{32}+a_{13}=(-1)^5\begin{vmatrix}3&3\\2&-1\end{vmatrix}+3=12$ (IV) (C) $A=3\begin{vmatrix}1&-1\\-3&2\end{vmatrix}+2\begin{vmatrix}2&-1\\4&2\end{vmatrix}+3\begin{vmatrix}2&1\\4&-3\end{vmatrix}=-17$ (I) (D) $a_{13} A_{12}+a_{23} A_{22}+a_{33} A_{32}=0$ (III) |