In a common emitter amplifier the audio signal voltage across the collector resistance of 2 kΩ is 2 V. The current amplification factor in 50. The value of base current is

20 μA

The correct answer is Option (1) → 20 μA

Using Ohm's law,

$I_C=\frac{V_C}{R_C}=\frac{2}{2000}=1mA$

The relationship between $I_B$ and $I_C$ is -

$I_C=β.I_B$

$⇒I_B=\frac{I_C}{β}=\frac{1mA}{50}=20μA$