A bag contains 17 tickets numbered 1 to 17. A ticket is drawn and replaced, then one more ticket is drawn and replaced. Probability that first number drawn is even and second is odd is

$\frac{72}{289}$

Let A be the event that first drawn number is even and B be event that the second drawn number is odd.

Total number of even numbers = $\left[\frac{17}{2}\right]=8$

$\Rightarrow P(A)=\frac{8}{47}$  and  $P(B)=\frac{9}{17} \Rightarrow P(A \cap B)=\frac{72}{289}$