A letter is known to have come either from KOLKATA or TATANAGAR. On the envelope just two consecutive letters TA are visible. The probability that letter has come from TATANAGAR is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{3}{5}$
Let $E_1$: Letter from KOLKATA, $E_2$: Letter from TATANAGAR.
$P(E_1) = \frac12, \quad P(E_2) = \frac12$
Event $A$: The two consecutive letters "TA" are visible.
For KOLKATA:
Letters: K O L K A T A
Number of 2-letter sequences = $7-1=6$
"TA" occurs only once ⇒ $P(A|E_1) = \frac16$
For TATANAGAR:
Letters: T A T A N A G A R
Number of 2-letter sequences = $9-1=8$
"TA" occurs twice ⇒ $P(A|E_2) = \frac28 = \frac14$
Bayes' theorem:
$P(E_2|A) = \frac{P(E_2) \cdot P(A|E_2)}{P(E_1) \cdot P(A|E_1) + P(E_2) \cdot P(A|E_2)}$
$= \frac{\frac12 \cdot \frac14}{\frac12 \cdot \frac16 + \frac12 \cdot \frac14}$
$= \frac{\frac18}{\frac{1}{12} + \frac18}$
LCM of 12 and 8 is 24:
$= \frac{\frac{3}{24}}{\frac{2}{24} + \frac{3}{24}}$
$= \frac{3}{5}$