Let f : R → R defined by $f(x)=x^3+x^2+100x+5\sin x$, then f is
Answer & explanation
Correct answer: option 3
$f(x)=x^3+x^2+100x+5\sin x$
$∴ f'(x) =3x^2+ 2x +100 +5\cos x$
$=3x^2+ 2x +94+(6+5\cos x)>0$
∴ is an increasing function and consequently a one-one function.
Clearly $f(−∞) = −∞, f(∞) = ∞$ and f(x) is continuous, therefore range f = R = codomain f.
Hence f is onto.