If the corresponding angles of two triangles are equal and satisfy , then $\frac{PX}{ER}=\frac{ZX}{RF}=\frac{PZ}{EF}$, then :

ΔPXZ is similar to ΔERF

$\frac{PX}{ER}=\frac{ZX}{RF}=\frac{PZ}{EF}$

That means ,

PX is corresponding to ER

ZX is corresponding to RF

PZ is corresponding to EF

Or we can say that X and R are corresponding angle, Z and F are corresponding angle & P and E are corresponding angles.

Hence we can conclude that ,

ΔPXZ is similar to ΔERF