If the corresponding angles of two triangles are equal and satisfy , then $\frac{PX}{ER}=\frac{ZX}{RF}=\frac{PZ}{EF}$, then :
Answer & explanation
Correct answer: option 2
$\frac{PX}{ER}=\frac{ZX}{RF}=\frac{PZ}{EF}$
That means ,
PX is corresponding to ER
ZX is corresponding to RF
PZ is corresponding to EF
Or we can say that X and R are corresponding angle, Z and F are corresponding angle & P and E are corresponding angles.
Hence we can conclude that ,
ΔPXZ is similar to ΔERF