Match List-I with List-II.
| List-I | List-II | ||
|---|---|---|---|
| (A) | Alkane | (I) | C2H5 |
| (B) | Alkyl | (II) | C2H6 |
| (C) | Alkyne | (III) | C2H4 |
| (D) | Alkene | (IV) | C2H2 |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → A-II, B-I, C-IV, D-III
The hydrocarbon families have general formulas: alkane CnH2n+2 (single bonds), alkene CnH2n (one double bond) and alkyne CnH2n−2 (one triple bond). An alkyl group is an alkane with one hydrogen removed, CnH2n+1. All four formulas here have two carbons (n = 2).
(A) Alkane — this matches (II) C2H6. This is ethane: 2 × 2 + 2 = 6 hydrogens, all bonds single.
(B) Alkyl — this matches (I) C2H5. This is the ethyl group, ethane less one hydrogen; it bonds to another atom through the free place.
(C) Alkyne — this matches (IV) C2H2. This is ethyne (acetylene), with a carbon–carbon triple bond: 2 × 2 − 2 = 2 hydrogens.
(D) Alkene — this matches (III) C2H4. This is ethene (ethylene), with a carbon–carbon double bond: 2 × 2 = 4 hydrogens.