If $\vec d=λ(\vec a×\vec b)+μ(\vec b×\vec c)+v(\vec c×\vec a)$ and $[\vec a\,\vec b\,\vec c]=\frac{1}{8}$, then $λ+μ+v$ is equal to:
Answer & explanation
Correct answer: option 4
$\vec d.\vec a=\frac{μ}{8};\vec d.\vec b=\frac{v}{8};\vec d.\vec c=\frac{λ}{8}$
$λ+μ+v=8\vec d.(\vec a+\vec b+\vec c)$