Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

The principle value of $cos^{-1}\left(-\frac{1}{2}\right)$ is :

Options:

$\frac{2\pi }{3}$

$-\frac{2\pi }{3}$

$\frac{\pi }{6}$

$-\frac{\pi }{6}$

Correct Answer:

$\frac{2\pi }{3}$

Explanation:

$\cos^{-1}\left(-\frac{1}{2}\right)=π-\left(\cos^{-1}\left(-\frac{1}{2}\right)\right)$

$=π-\frac{π}{3}$

$=\frac{2π}{3}$