The ionisation energy of hydrogen atom is 13.6 eV. Following Bohr's theory, the energy corresponding to a transition between the 3rd and the 4th orbit is
Answer & explanation
Correct answer: option 4
$E_3=-\frac{13.6}{9}=-1.51 ~eV ; \quad E_4=-\frac{13.6}{16}=-0.85 ~eV$
∴ $E_4-E_3=0.66 ~eV$