Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is -

Options:

\(\frac{1}{\sqrt{2}}\)

2

\(\sqrt{2}\)

\(\frac{1}{2}\)

Correct Answer:

\(\frac{1}{2}\)

Explanation:

Potential Energy : U = \(-\frac{GMm}{r}\)

Kinetic Energy : K = \(\frac{1}{2} mv^2\) ; velocity : v = \(\sqrt{\frac{GM}{r}}\)

⇒ Kinetic Energy : K = \(\frac{1}{2}\frac{GMm}{r}\)

∴ Ratio : \(\frac{K}{U} = \frac{1}{2}\)