Current and voltage in an a. c. circuit are given as
$I= 10 \sin (50 t-π/2) А$
$V= 200 \sin (50 t) V$ (t represents time)
The power dissipated in the circuit is

0 W

The correct answer is Option (3) → 0 W

Current: $I = 10\sin(50t - \frac{\pi}{2})$

Voltage: $V = 200\sin(50t)$

Phase difference: $\phi = \frac{\pi}{2}$

Average power: $P = VI \cos\phi$

Here $V_{rms} = \frac{200}{\sqrt{2}}, \; I_{rms} = \frac{10}{\sqrt{2}}$

$P = V_{rms} I_{rms} \cos\phi$

$P = \frac{200}{\sqrt{2}} \cdot \frac{10}{\sqrt{2}} \cdot \cos\frac{\pi}{2}$

$P = 1000 \cdot 0 = 0$

Final Answer: $0 \; \text{W}$