CUET Preparation Today
If x is a positive mal number , then what is the smallest value of $\frac{x^2+361}{x}$ ? |
45 42 38 35 |
38 |
The correct answer is option (3) : 38 Since $A.M ≥ G.M$ $\frac{x^2+361}{2}≥\sqrt{x^2.361}$ $\frac{x^2+361}{2}≥19x$ $\frac{x^2+361}{2}≥38$ Hence, the smallest value of $\frac{x^2+361}{2}$ is 38. |
