If x is a positive mal number , then what is the smallest value of $\frac{x^2+361}{x}$ ?
Answer & explanation
Correct answer: option 3
The correct answer is option (3) : 38
Since $A.M ≥ G.M$
$\frac{x^2+361}{2}≥\sqrt{x^2.361}$
$\frac{x^2+361}{2}≥19x$
$\frac{x^2+361}{2}≥38$
Hence, the smallest value of $\frac{x^2+361}{2}$ is 38.