Shaded region in the figure shows the feasible solutions for a LPP. If the objective function $Z=ax+6y$ attains the maximum value at both the points (4, 10) and (6, 9) then the maximum value of Z is :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 72
The objective function is,
$Z=ax+6y$
$Z(4,10)=Z(6,9)$
$4a+60=6a+54$
$2a=6$
$a=3$
$⇒Z(4,10)=4×3+60=72$