Practicing Success
Practicing Success
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If $\frac{x}{y}+\frac{y}{x}=2,(x, y \neq 0)$, then the value of $(x-y)$ is : |
1 0 2 -2 |
0 |
If $\frac{x}{y}+\frac{y}{x}=2,(x, y \neq 0)$ then the value of $(x-y)$ is = ? If $\frac{x}{y}+\frac{y}{x}=2,(x, y \neq 0)$ = \(\frac{x^2 + y^2}{xy}\) = 2 = x2 + y2 - 2xy = 0 = (x - y)2 = 0 = x - y = 0 |
