If $\frac{x}{y}+\frac{y}{x}=2,(x, y \neq 0)$, then the value of $(x-y)$ is :
Answer & explanation
Correct answer: option 2
If $\frac{x}{y}+\frac{y}{x}=2,(x, y \neq 0)$
then the value of $(x-y)$ is = ?
If $\frac{x}{y}+\frac{y}{x}=2,(x, y \neq 0)$
= \(\frac{x^2 + y^2}{xy}\) = 2
= x2 + y2 - 2xy = 0
= (x - y)2 = 0
= x - y = 0