In the given figure ABCD is a rhombous, if ∠ACD = 40°, then x is:
Answer & explanation
Correct answer: option 1
In a rhombus opposite angles are equal and diagonals bisect each others at right angle.
\(\angle\) ACD = \(\angle\) CAD = 40°
\(\angle\) CAD = \(\angle\) CAB = 40° [diagonal bisect the angles]
In ΔABO,
\(\angle\) AOB = 90° , \(\angle\) OAB = 40°
Therefore,
\(\angle\) ABO = x° = 90° - 40° = 50°