If tanθ = \(\frac{12}{5}\)
find the value of \(\frac{24cotθ - 5cosθ+5}{13cosθ + 5tanθ-1}\) .
Answer & explanation
Correct answer: option 3
tanθ = \(\frac{12}{5}\) = \(\frac{P}{B}\) (Triplet 5 , 12 , 13)
B = 13
Put than and find
⇒ \(\frac{24cotθ - 5cosθ+1}{13cosθ + 5tanθ-1}\)
⇒ \(\frac{24×\frac{5}{12} - 5 ×\frac{13}{5}+5}{13\frac{5}{13}+5×\frac{12}{5}-1}\)
⇒ \(\frac{10 - 13 + 5 }{5 + 12 -1}\)
⇒ \(\frac{2}{16}\)
= \(\frac{1}{8}\)