Akbar runs \(\frac{7}{2}\) times as fast as Birbal. In a race, Akbar gives Birbal a start of 80 m. At what distance from Akbar's starting point will Akbar catch up with Birbal?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 112 m
Both run for the same time until they meet, so the distances they cover are in the ratio of their speeds, 7 : 2. Birbal starts 80 m ahead, so he covers 80 m less than Akbar.
Let Akbar cover \(x\) m; then Birbal covers \((x-80)\) m
\(\displaystyle \frac{x}{x-80}=\frac{7}{2}\), so \(2x=7x-560\)
\(5x=560\), so \(x=112\) m