A certain distance is covered by a cyclist at a certain speed.  If a jogger covers one third of the distance in four times of the time.  The ratio of speed of the jogger to that of the cyclist is:

1 : 12

Let the distance covered by the cyclist is d and the time taken to cover the distance is T.

So, ATQ,

The speed of the cyclist (S₁) = \(\frac{d}{T}\)

Now, the speed of the jogger (S₂) = \(\frac{\frac{d}{3}}{4T}\) = \(\frac{d}{12T}\)

⇒ S₂ : S₁ = \(\frac{d}{12T}\) : \(\frac{d}{T}\)

⇒ S₂ : S₁ = 1 : 12