Let X denote the number of hours a person watches television during a randomly selected day. The probability that X can take the values $x_i$ has the following form, where k is some unknown constant. $P(X = x;) =\left\{\begin{matrix}0.2,&if\,x_i=0\\Kx_i,& if\, x_i = 1\, or\, 2\\k (5-x_i),&if\, x_i = 3\\0,&otherwise\end{matrix}\right.$ Find the variance and standard deviation of random variable X. |
Variance = 1.01, Standard Deviation = 1.1 Variance = 0.96, Standard Deviation = 1.1 Variance = 0.99, Standard Deviation = 1.5 Variance = 1.22, Standard Deviation = 1.1 |
Variance = 1.22, Standard Deviation = 1.1 |
The correct answer is Option (4) → Variance = 1.22, Standard Deviation = 1.1 From the given information, we find that the probability distribution of X is
We know that $Σp_i = 1$ $⇒ 0.2+k+2k + 2k = 1$ $⇒ 5k=0.8⇒k=\frac{4}{25}$ We construct the following table:
$E(X) = Σp_ix_i=\frac{44}{25}= 1.76$ Variance $σ^2 = Σp_i{x_i}^2 - (Σp_ix_i)^2$ $=\frac{44}{25}-(\frac{44}{25})^2=\frac{108}{25}-\frac{1936}{625}=\frac{764}{625}= 1.22$ and standard deviation $σ =\sqrt{Variance}=\sqrt{1.22} = 1.1$ |