In a hydrogen atom, the distance between the electron and proton is $2.5 × 10^{-11}$ m. The electrical force of attraction between them will be
Answer & explanation
Correct answer: option 2
$F=\frac{9 × 10^9 × 1.6 × 10^{-19} × 1.6 × 10^{-19}}{\left(2.5 × 10^{-11}\right)^2} = 3.7 × 10^{-7}$ N