Practicing Success
The magnitude of gravitational potential energy of the earth-satellite system is U with zero potential energy at infinite separation. The kinetic energy of satellite is K. Mass of satellite << mass of the earth. Then |
K = 2U K = $\frac{U}{2}$ K = U K = 4U |
K = 2U |
Kinetic energy of the satellite K = $\frac{GMm}{2r}$ while magnitude of the potential energy U = $\frac{GMm}{r}$ Hence K = $\frac{U}{2}$ |