Which compound of transition metal is used as a catalyst in the Contact Process? |
Copper (II) oxide Manganese (IV) oxide Iron (III) oxide Vanadium (V) oxide |
Vanadium (V) oxide |
The correct answer is Option (4) → Vanadium (V) oxide Vanadium (V) oxide, also known as vanadium pentoxide ($V_2O_5$), is the essential catalyst used in the Contact Process for the industrial manufacture of sulfuric acid ($H_2SO_4$). Role in the Contact Process The Contact Process involves the oxidation of sulfur dioxide ($SO_2$) to sulfur trioxide ($SO_3$). This reaction is highly exothermic and reversible: $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) \quad \Delta H = -196 \text{ kJ/mol}$ In the presence of the $V_2O_5$ catalyst at temperatures between 400°C and 450°C, the reaction reaches equilibrium much faster. Mechanism of Catalysis The catalytic activity of $V_2O_5$ is a perfect example of how transition metals use their variable oxidation states to facilitate a reaction: Oxidation of $SO_2$: The sulfur dioxide reacts with the vanadium (V) oxide. The vanadium is reduced from its +5 oxidation state to +4, while the $SO_2$ is oxidized to $SO_3$: $V_2O_5 + SO_2 \rightarrow V_2O_4 + SO_3$ Regeneration of Catalyst: The vanadium (IV) oxide then reacts with oxygen from the air to be oxidized back to vanadium (V) oxide, completing the catalytic cycle: $2V_2O_4 + O_2 \rightarrow 2V_2O_5$ Comparison with other options
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