Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Semiconductors and Electronic Devices

Question:

A zener diode, having breakdown voltage equal to 15V, is used in a voltage regulator circuit shown in figure. The current through the diode is

Options:

10 mA

15 mA

20 mA

5 mA

Correct Answer:

5 mA

Explanation:

Voltage across Zener diode is constant.

Current in 1kΩ resistor.

$(i)_{1kΩ}\frac{15volt}{1kΩ}=15mA$

Current in 250Ω resistor,

$(i)_{250Ω}=\frac{(20-15)V}{250Ω}=\frac{5}{250Ω}$

$=\frac{20}{1000}A=20mA$

$∴(i)_{zener\, diode} = (20 −15) = 5mA$