What is the force experienced by an electron moving with velocity of 0.5c in a magnetic field $\vec{B}$ of 2T? The angle between the velocity vector and $\vec{B}$ is 90°. (c is the velocity of light, $e=1.6 \times 10^{-19} C$) |
$4.8 \times 10^{-10} N$ $4.8 \times 10^{-11} N$ $4.8 \times 10^{-12} N$ $4.8 \times 10^{-13} N$ |
$4.8 \times 10^{-12} N$ |
The correct answer is Option (3) → $4.8 \times 10^{-12} N$ Since the angle between the velocity vector and magnetic field is 90°, the force is at its maximum. $F=|q|vB$ [Lorentz force] $=(1.6×10^{-19})×(1.5×10^8)×2$ $=4.8×10^{-11}N$ |