Jeep A and Jeep B are competing in a motor race. After starting together, Jeep B covers the target of 30 km in 30 min 04 sec. Jeep A covers the target in 30 min 01 sec. By what distance will Jeep A beat Jeep B ?

50 m

Distance of race $=30$ km.

Time taken by Jeep B $=30$ min $04$ s $=1804$ s.

Time taken by Jeep A $=30$ min $01$ s $=1801$ s.

Speed of Jeep A $=\frac{30}{1801}$ km/s.

In $1804$ s, distance covered by Jeep A:

$=\frac{30}{1801}\times1804=\frac{54120}{1801}$ km.

Distance covered by Jeep B in $1804$ s $=30$ km.

Distance by which Jeep A beats Jeep B:

$=\frac{54120}{1801}-30=\frac{54120-54030}{1801}=\frac{90}{1801}$ km.

$=\frac{90}{1801}\times1000 \approx 49.97$ m.

final answer: Jeep A beats Jeep B by approximately $50$ metres