If cos 27° = x, then the value of tan 63° is :

$\frac{\sqrt{1+x^2}}{x}$ $\frac{x}{\sqrt{1+x^2}}$ $\frac{\sqrt{1-x^2}}{x}$ $\frac{x}{\sqrt{1-x^2}}$

$\frac{x}{\sqrt{1-x^2}}$

cos 27° = x cos θ =  \(\frac{B }{H}\) =  \(\frac{x }{1}\) P² + B² = H²  P² + x² = 1² P = \(\sqrt { 1 - x² }\) We know , tan 63° = cot 27° So , cot 27° =  \(\frac{x }{\sqrt { 1 - x² }\ }\