The population of a town is 80,000. It decreases by 8% in the first year and increases by 5% in the second year. What will be the population of the town at the end of 2 years?

77280

Formula:-

Net percentage change = [ -A + B - \(\frac{(A×B )}{100}\) ]%

Net percentage change in 2 years = - 8% + 5% - \(\frac{(8×5 )}{100}\)%

= - 3.4%

Population of the town at the end of 2 years = \(\frac{96.6}{100}\) × 80000

= 77280

 So , population after 2 years = 77280