Practicing Success
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Observe the above figure and answer the question. |
The length of AB is: |
149 cm 12 cm 13 cm \(\sqrt {149}\) |
\(\sqrt {149}\) |
In Δ ADC, \(\angle\)D =90° By using pythagoras theorem: AC2 = AD2 + DC2 AC2 = 62 + 82 = 36 + 64 = 100 AC = 10 cm In Δ ACB, \(\angle\)C =90° By using pythagoras theorem: AB2 = AC2 + CB2 AB2 = 102 + 72 = 100 + 49 = 149 AB = \(\sqrt {149}\) cm |
