$\int\left(e^{\log x}+\sin x\right) \cos x d x$ is equal to
Answer & explanation
Correct answer: option 3
$e^{log x} = x$
$I=\int x \cos x d x+\int \sin x \cos x d x=x \sin x+\cos x-\frac{\cos ^2 x}{2}+c$
Hence (3) is the correct answer.
$\int\left(e^{\log x}+\sin x\right) \cos x d x$ is equal to
Correct answer: option 3
$e^{log x} = x$
$I=\int x \cos x d x+\int \sin x \cos x d x=x \sin x+\cos x-\frac{\cos ^2 x}{2}+c$
Hence (3) is the correct answer.