Practicing Success
A is more efficient than B and they together can complete a work in 24 days. Had A done 50% of the work and then B, the remaining work, then the work would have been done in 50 days. B alone will complete 40% of the same work in: |
16 days 24 days 21 days 20 days |
24 days |
Let work done per unit day by A = a unit, And, work done per unit by B = b unit, Now, total work = (a + b) x 24 units, According to the question, [12(a + b)/a] = [ 12(a+b)/b] = 50, As, we have 2 variables, and 1 equation, we can assume value for one variable, Lets, take a = 1, [12(1 +b)/1] = [12(1 + b)/b] = 50, ⇒ 12 + 12b = 12/b + 12 = 50, ⇒ 12b + 12/b = 26 ⇒ 6b + (6/b) = 13, ⇒ 6b2+ 6 = 13b ⇒ 6b2 - 13b + 6 = 0. ⇒ 3b(2b - 3) - 2(2b - 3) = 0 ⇒ (3b - 2)(2b - 3) = 0 ⇒ b = \(\frac{2}{3}\) or \(\frac{3}{2}\) As, a > b, b = \(\frac{2}{3}\) Now, total work = (1 + \(\frac{2}{3}\)) x 24 = 40 units, 40% of total work = 40 x 40% = 16 units, Hence, Time taken by B = \(\frac{16}{2/3}\) = 24 days. |