X-rays of wavelength 10.0 pm are scattered from a target. The wavelength of the X-rays scattered through 30° is:
Answer & explanation
Correct answer: option 1
The change in wavelength is given by
$Δλ=λ'-λ=\frac{h}{m_0c}(1-\cos\phi)$
Where, λ' = wavelength of the X-rays scattered
and $λ_c=\frac{h}{m_0c}$ = compton wavelength = $2.426×10^{-12}m$
$⇒λ' =λ+λ_c(1-\cos 30°)=10pm+0.134λ_c=10.32pm$