Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

X-rays of wavelength 10.0 pm are scattered from a target. The wavelength of the X-rays scattered through 30° is:

Options:

10.32 pmn

12 pm

10 nm

10 Å

Correct Answer:

10.32 pmn

Explanation:

The change in wavelength is given by

$Δλ=λ'-λ=\frac{h}{m_0c}(1-\cos\phi)$

Where, λ' = wavelength of the X-rays scattered

and $λ_c=\frac{h}{m_0c}$ = compton wavelength = $2.426×10^{-12}m$

$⇒λ' =λ+λ_c(1-\cos 30°)=10pm+0.134λ_c=10.32pm$