Practicing Success
X-rays of wavelength 10.0 pm are scattered from a target. The wavelength of the X-rays scattered through 30° is: |
10.32 pmn 12 pm 10 nm 10 Å |
10.32 pmn |
The change in wavelength is given by $Δλ=λ'-λ=\frac{h}{m_0c}(1-\cos\phi)$ Where, λ' = wavelength of the X-rays scattered and $λ_c=\frac{h}{m_0c}$ = compton wavelength = $2.426×10^{-12}m$ $⇒λ' =λ+λ_c(1-\cos 30°)=10pm+0.134λ_c=10.32pm$ |