Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Determinants

Question:

If A is square matrix such that A2 = A, then (I + A)3 - 8A is equal to :

Options:

I

A

I - A

3A

Correct Answer:

I - A

Explanation:

A2 = A

so (I + A)3 - 8A

(I + A)3 = (I + A)(I + A)(I + A)

= (I + A + A + A2)(I + A)(A2 + 2A + I)(I + A)

= A3 + 2A2 + A + A2 + 2A + I

= A3 + 3A2 + 3A + I

⇒ A3 + 3A2 + 3A + I - 8A

= AA + 3A + 3A + I - 8A

A + 3A + 3A + I - 8A

⇒ I - A