At a distance of 2 m, the electric field due to a source charge is \( 24\,\mathrm{N\,C^{-1}} \). What will be the force experienced by a charge of 2 C placed there?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 48 N
The electric field at a point is the force that a unit positive charge would feel if placed there. So a charge \( q \) placed at a point where the field is \( E \) feels a force \( F=qE \). The distance of 2 m only tells where the field is \( 24\,\mathrm{N\,C^{-1}} \).
\( \begin{aligned} F &= qE \\ &= 2\,\mathrm{C}\times24\,\mathrm{N\,C^{-1}} \\ &= 48\,\mathrm{N} \end{aligned} \)