A pair of tangents AB and AC are drawn from a point which is at a distance of 13 cm from the center O of a circle of radius 5 cm, then the area in cm² of quadrilateral ABOC is?

60 cm²

OB ⊥ AB, right angle at B

Therefore, in right angle triangle, using triplets = 5, 12, 13

Area of quadrilateral ABOC = 2 × Area of ΔABO

                                           = 2 × \(\frac{1}{2}\) × 5 × 12

                                           = 60 cm²