A pair of tangents AB and AC are drawn from a point which is at a distance of 13 cm from the center O of a circle of radius 5 cm, then the area in cm2 of quadrilateral ABOC is?
Answer & explanation
Correct answer: option 1
OB ⊥ AB, right angle at B
Therefore, in right angle triangle, using triplets = 5, 12, 13
Area of quadrilateral ABOC = 2 × Area of ΔABO
= 2 × \(\frac{1}{2}\) × 5 × 12
= 60 cm2