Practicing Success
If radius of the circumcircle of an equilateral triangle is 8 cm; then the measure of radius of its incircle is: |
4 cm 4\(\sqrt {3}\) cm 8\(\sqrt {3}\) cm 12 cm |
4 cm |
Radius of circumcircle = \(\frac{a}{\sqrt {3}}\) = 8 and radius of incircle = \(\frac{a}{2 \sqrt {3}}\) Therefore, radius of incircle = \(\frac{8}{2}\) = 4 cm Or Note: In equilateral triangle the ratio of circumradius to inradius is 2 : 1. Therefore, If Circumradius = 8 cm, then inradius = 4cm |