The area of the smaller portion enclosed by the circle $x^2+y^2=4 $ and the straight line $x+y = 2 $ is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\pi - 2 $
So area required = area of quarter circle - area of triangle
$=\frac{4\pi}{4}-\frac{1}{2}×2×2$
$=\pi-2$