In a bag there are 15 red and 5 white balls. Two balls are drawn in succession, without replacement. The first drawn ball is found to be red. The probability that second ball is also red, is equal to

$\frac{14}{19}$

Total number of ways of selecting the second ball $={ }^{19} C_1=19$.

Total number of ways of selecting the second ball suitably $={ }^{14} C_1=14$.

Thus, required probability $\frac{14}{19}$.