The correct answer is Option (3) → (A), (C), (D), (B) CH₃CH₂CH₂CH₃ < C₂H₅OC₂H₅ < CH₃CH₂CH₂CHO < CH₃CH₂CH₂CH₂OH The order of increasing boiling point for the given compounds is Butane < Diethyl ether < Butanal < Butanol
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(A) CH₃CH₂CH₂CH₃ – Butane Non-polar molecule. Only London dispersion forces act. Hence lowest boiling point.
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(C) C₂H₅OC₂H₅ – Diethyl ether Slightly polar due to C–O–C bond, so dipole–dipole forces are present, but no hydrogen bonding. Boiling point increases slightly.
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(D) CH₃CH₂CH₂CHO – Butanal Contains C=O (carbonyl) group, which is strongly polar. Stronger dipole–dipole attraction than ether, so higher boiling point.
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(B) CH₃CH₂CH₂CH₂OH – Butanol Has –OH group, enabling intermolecular hydrogen bonding, which is the strongest intermolecular force among these. Hence highest boiling point.
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