Practicing Success
$\lim\limits_{n \rightarrow \infty}\left\{\frac{n}{n^2+1^2}+\frac{n}{n^2+2^2}+...+\frac{n}{n^2+n^2}\right\}$, is equal to |
1 0 $\frac{\pi}{4}$ $\frac{\pi}{2}$ |
$\frac{\pi}{4}$ |
Let $S=\lim\limits_{n \rightarrow \infty}\left\{\frac{n}{n^2+1^2}+\frac{n}{n^2+2^2}+...+\frac{n}{n^2+n^2}\right\}$ $\Rightarrow S=\lim\limits_{n \rightarrow \infty} \sum\limits_{r=1}^n \frac{n}{n^2+r^2}=\frac{1}{n} \lim\limits_{n \rightarrow \infty} \sum\limits_{r=1}^n \frac{1}{1+(r / n)^2}$ $\Rightarrow S=\int\limits_0^1 \frac{1}{1+x^2} d x=\left[\tan ^{-1} x\right]_0^1=\tan ^{-1} 1-\tan ^{-1} 0=\frac{\pi}{4}$ |