In a series LCR circuit the voltage across the resistance, capacitance and inductance is 10 V each. If the capacitance is short circuited, the voltage across the inductance will be

$10 V$

The voltages across all the three components are equal, so the impedance will be the same.

$\Rightarrow R = X_L$

$ I = \frac{V}{\sqrt {R^2+ X_L^2}} = \frac{10}{R\sqrt 2}$

Potential drop across inductor is $V_L = IX_L = \frac{10}{\sqrt 2}$